√70以上 2x^3y'=y(y^2 3x^2) bernoulli 269035

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2x^3y'=y(y^2 3x^2) bernoulli-Get an answer for 'solve first grade ecuation with bernoulli dy/dx = (y^22xy)/x^2 general ecuation and particular when y(1)=1' and find homework help for other Math questions at eNotesY(4) = 2 1 Rewriting the LHS in di erential form and factoring the RHS we get dy dx = (x 2)(y 1) (x 3)(y 1) 2 Separating the variables leads to y 1 y 1 dy = x 2 x 3 dx 3 To evaluate the integrals Z y 1 y 1 dy = Z x 2 x 3 dx we need usubstitution on both sides On the LHS, let u = y 1 and then du = dy